pPhenylenediamine | C6H4(NH2)2 or C6H8N2 | CID 7814 - structure, chemical names, physical and chemical properties, classification, patents, literature, biological
Consider the form . Find a pair of integers whose product is and whose sum is . In this case, whose product is and whose sum is .
Question276406: Given that P(A or B) = 1/3, P(A) = 1/6, and P(A and B) = 1/8, find P(B). 7/24 is the answer but I would really love to know why. This question is worded in a very confusing manner. Found 2 solutions by stanbon, edjones:
Dado um polinômio px, temos que seu valor numérico é tal que x = a é um valor que se obtém substituindo x por a, onde a pertence ao conjunto dos números reais. Dessa forma, concluímos que o valor numérico de pa corresponde a px onde x = a. Por exemplo, dado o polinômio px = 4x² – 9x temos que seu valor numérico para x = 2 é calculado da seguinte maneira px = 4x² – 9x p2 = 4 * 2² – 9 * 2 p2 = 4 * 4 – 18 p2 = 16 – 18 p2 = –2 Se, ao calcularmos o valor numérico de um polinômio determinarmos pa = 0, temos que esse número dado por a corresponde à raiz do polinômio px. Observe o polinômio px = x² – 6x + 8 quando aplicamos p2 = 0. p2 = 2² – 6 * 2 + 8 p2 = 4 – 12 + 8 p2 = 12 – 12 p2 = 0 Dessa forma, percebemos que o número 2 é raiz do polinômio px = x² – 6x + 8, pois temos que p2 = 0. Exemplo 1 Dado o polinômio px = 4x³ – 9x² + 8x – 10, determine o valor numérico de p3. p3 = 4 * 3³ – 9 * 3² + 8 * 3 – 10 p3 = 4 * 27 – 9 * 9 + 24 – 10 p3 = 108 – 81 + 24 – 10 p3 = 41 O valor de px = 4x³ – 9x² + 8x – 10 para p3 é 41. Exemplo 2 Determine o valor numérico de px = 5x4 – 2x³ + 3x² + 10x – 6, para x = 2. p2 = 5 * 24 – 2 * 23 + 3 * 22 + 10 * 2 – 6 p2 = 5 * 16 – 2 * 8 + 3 * 4 + 20 – 6 p2 = 80 – 16 + 12 + 20 – 6 p2 = 90 De acordo com o polinômio fornecido temos que p2 = pare agora... Tem mais depois da publicidade ;
fory = 0,1,2,3; which is an instance of the law of total probability. Conditioning on the level of densities The result P ( Y ≤ 0.75 | X = 0.5 ) = 5/6, mentioned above, is geometrically evident in the following sense. The points (x,y,z) of the sphere x 2 + y 2 + z 2 = 1,
In fact the result holds a bit more generally, namely Lemma $\rm\ \ 24\ \ M^2 - N^2 \;$ if $\rm \; M,N \perp 6, \;$ coprime to $6.\;$ Proof $\rm\ \ \ \ \ N\perp 2 \;\Rightarrow\,\bmod 8\!\,\ N = \pm 1, \pm 3 \,\Rightarrow\, N^2\equiv 1$ $\rm\qquad\qquad N\perp 3 \;\Rightarrow\,\bmod 3\!\,\ N = \pm 1,\ $ hence $\rm\ N^2\equiv 1$ Thus $\rm\ \ 3, 8\ \ N^2 - 1 \;\Rightarrow\; 24\ \ N^2 - 1 \ $ by $\ {\rm lcm}3,8 = 24,$ by $\,\gcd3,8=1,\,$ or by CCRT. Remark $ $ It's easy to show that $\,24\,$ is the largest natural $\rm\,n\,$ such that $\rm\,n\mid a^2-1\,$ for all $\rm\,a\perp n.$ The Lemma is a special case $\rm\ n = 24\ $ of this much more general result Theorem $\ $ For naturals $\rm\ a,e,n $ with $\rm\ e,n>1 $ $\rm\quad n\ \ a^e-1$ for all $\rm a\perp n \ \iff\ \phi'p^k\\e\ $ for all $\rm\ p^k\\n,\ \ p\$ prime with $\rm \;\;\; \phi'p^k = \phip^k\ $ for odd primes $\rm p\,\ $ where $\phi$ is Euler's totient function and $\rm\ \quad \phi'2^k = 2^{k-2}\ $ if $\rm k>2\,\ $ else $\rm\,2^{k-1}$ The latter exception is due to $\rm \mathbb Z/2^k$ having multiplicative group $\,\rm C2 \times C2^{k-2}\,$ for $\,\rm k>2$. Notice that the least such exponent $\rm e$ is given by $\rm \;\lambdan\; = \;{\rm lcm}\;\{\phi'\;{p_i}^{k_i}\}\;$ where $\rm \; n = \prod {p_i}^{k_i}\;$. $\rm\lambdan$ is called the universal exponent of the group $\rm \mathbb Z/n^*,\;$ the Carmichael function. So the case at hand is simply $\rm\ \lambda24 = lcm\phi'2^3,\phi'3 = lcm2,2 = 2\.$ See here for proofs and further discussion.
Textbooksolution for Multivariable Calculus 8th Edition James Stewart Chapter 14.7 Problem 57E. We have step-by-step solutions for your textbooks written by Bartleby experts!
Let be a polynomial of degree 4, with , and . Then the value of is
Solutionfor P(3, -2, -1), Q(1, 5, 4), R(2, 0, -6), S(-4, 1, 5) find proj PS. QR
Algebra Examples Popular Problems Algebra Solve for p 3p-3-5p>-3p-6 Step 1Simplify .Tap for more steps...Step each for more steps...Step the distributive by .Step from .Step 2Move all terms containing to the left side of the for more steps...Step to both sides of the and .Step 3Move all terms not containing to the right side of the for more steps...Step to both sides of the and .Step 4The result can be shown in multiple FormInterval Notation
拟试教人员名单开阳县2022年"特岗教师"招聘递补考生试教人员名单 序号 姓名 准考证号 性别 民族 报考县 报考学段
Sothe p values can be found using the following R command: > pt (t, df =pmin( num1, num2)-1) [1] 0.01881168 0.00642689 0.99999998. If you enter all of these commands into R you should have noticed that the last p value is not correct. The pt command gives the probability that a score is less that the specified t.
. pl6k3a4e5t.pages.dev/124pl6k3a4e5t.pages.dev/396pl6k3a4e5t.pages.dev/68pl6k3a4e5t.pages.dev/22pl6k3a4e5t.pages.dev/341pl6k3a4e5t.pages.dev/284pl6k3a4e5t.pages.dev/342pl6k3a4e5t.pages.dev/79pl6k3a4e5t.pages.dev/6
p 2 p 3 1 p 6
